-50=20x-4.9x^2

Solution for -50=20x-4.9x^2 equation:

-50=20x-4.9x^2

We move all terms to the left:

-50-(20x-4.9x^2)=0

We get rid of parentheses

4.9x^2-20x-50=0

a = 4.9; b = -20; c = -50;
Δ = b2-4ac
Δ = -202-4·4.9·(-50)
Δ = 1380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1380}=\sqrt{4*345}=\sqrt{4}*\sqrt{345}=2\sqrt{345}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{345}}{2*4.9}=\frac{20-2\sqrt{345}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{345}}{2*4.9}=\frac{20+2\sqrt{345}}{9.8}
$